Nuprl Rule : isect_memberEquality_alt

This rule proved as lemma rule_isect_member_equality_true in file rules/rules_isect2.v
 at https://github.com/vrahli/NuprlInCoq  

H  ⊢ b1 b2 ∈ (⋂x:A. B)

  BY isect_memberEquality_alt ()
  
  z:A ⊢ b1 b2 ∈ B[z/x]
  H  ⊢ istype(A)


Latex:
H    \mvdash{}  b1  =  b2

    BY  isect\_memberEquality\_alt  z  ()
   
    H  z:A  \mvdash{}  b1  =  b2
    H    \mvdash{}  istype(A)



Date html generated: 2019_06_20-PM-04_11_46
Last ObjectModification: 2018_09_25-PM-02_09_45

Theory : rules


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