Nuprl Rule : lambdaEquality_alt

This rule proved as lemma rule_lambda_equality_true in file rules/rules_function.v
 at https://github.com/vrahli/NuprlInCoq  
H  ⊢ (λx1.b1) = (λx2.b2) ∈ (x:A ⟶ B)

  BY lambdaEquality_alt z ()
  
  H z:A ⊢ b1[z/x1] = b2[z/x2] ∈ B[z/x]
  H  ⊢ istype(A)

Latex:
H    \mvdash{}  (\mlambda{}x1.b1)  =  (\mlambda{}x2.b2)

    BY  lambdaEquality\_alt  z  ()
   
    H  z:A  \mvdash{}  b1[z/x1]  =  b2[z/x2]
    H    \mvdash{}  istype(A)


Date html generated: 2019_06_20-PM-04_11_42
Last ObjectModification: 2018_09_25-PM-02_11_00

Theory : rules


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