Nuprl Rule : sqequalSubstitution

This rule proved as lemma rule_cequiv_subst_concl_true3 in file rules/rules_squiggle2.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ T[a/x] ext t

  BY sqequalSubstitution (a ~ b) x.T ()

  H  ⊢ a ~ b
  H  ⊢ T[b/x] ext t

Definitions occuring in rule : sqequal: s ~ t, axiom: Ax

Latex:
H \mvdash{} T[a/x] ext t BY sqequalSubstitution (a \msim{} b) x.T () H \mvdash{} a \msim{} b H \mvdash{} T[b/x] ext t Date html generated: 2019_06_20-PM-04_11_39 Last ObjectModification: 2016_07_08-PM-03_48_47 Theory : rules Home Index