Nuprl Rule : unionEquality
This rule proved as lemma rule_union_equality_true in file rules/rules_union.v at https://github.com/vrahli/NuprlInCoq
H ⊢ (a1 + b1) = (a2 + b2) ∈ Type
BY unionEquality ()
H ⊢ a1 = a2 ∈ Type
H ⊢ b1 = b2 ∈ Type
Definitions occuring in rule :
union: left + right,
equal: s = t ∈ T,
universe: Type,
axiom: Ax
Latex:
H \mvdash{} (a1 + b1) = (a2 + b2)
BY unionEquality ()
H \mvdash{} a1 = a2
H \mvdash{} b1 = b2
Date html generated:
2019_06_20-PM-04_11_49
Last ObjectModification:
2016_07_08-PM-03_48_45
Theory : rules
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