Step * of Lemma padic_subtype_basic-padic

[p:ℤ]. (padic(p) ⊆basic-padic(p))
BY
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Latex:


Latex:
\mforall{}[p:\mBbbZ{}].  (padic(p)  \msubseteq{}r  basic-padic(p))


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Latex:
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