Nuprl Lemma : fpf-trivial-subtype-top
∀[A:Type]. ∀[B:A ⟶ Type]. ∀[f:a:A fp-> B[a]]. (f ∈ a:A fp-> Top)
Proof
Definitions occuring in Statement :
fpf: a:A fp-> B[a]
,
uall: ∀[x:A]. B[x]
,
top: Top
,
so_apply: x[s]
,
member: t ∈ T
,
function: x:A ⟶ B[x]
,
universe: Type
Definitions unfolded in proof :
uall: ∀[x:A]. B[x]
,
member: t ∈ T
,
subtype_rel: A ⊆r B
,
so_lambda: λ2x.t[x]
,
so_apply: x[s]
,
uimplies: b supposing a
,
all: ∀x:A. B[x]
,
top: Top
Latex:
\mforall{}[A:Type]. \mforall{}[B:A {}\mrightarrow{} Type]. \mforall{}[f:a:A fp-> B[a]]. (f \mmember{} a:A fp-> Top)
Date html generated:
2016_05_16-AM-11_03_47
Last ObjectModification:
2015_12_29-AM-09_12_37
Theory : event-ordering
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