Nuprl Lemma : assert-es-locless
∀es:EO. ∀x,y:es-base-E(es). ↑es-locless(es;x;y) ⇐⇒ (x < y) supposing loc(x) = loc(y) ∈ Id
Proof
Definitions occuring in Statement :
es-locless: es-locless(es;e1;e2),
es-causl: (e < e'),
es-loc: loc(e),
es-base-E: es-base-E(es),
event_ordering: EO,
Id: Id,
assert: ↑b,
uimplies: b supposing a,
all: ∀x:A. B[x],
iff: P ⇐⇒ Q,
equal: s = t ∈ T
Definitions unfolded in proof :
all: ∀x:A. B[x],
uall: ∀[x:A]. B[x],
member: t ∈ T,
uimplies: b supposing a,
iff: P ⇐⇒ Q,
and: P ∧ Q,
implies: P ⇒ Q,
es-causl: (e < e'),
squash: ↓T,
prop: ℙ,
rev_implies: P ⇐ Q
Latex:
\mforall{}es:EO. \mforall{}x,y:es-base-E(es). \muparrow{}es-locless(es;x;y) \mLeftarrow{}{}\mRightarrow{} (x < y) supposing loc(x) = loc(y)
Date html generated:
2016_05_16-AM-09_14_44
Last ObjectModification:
2016_01_17-PM-01_31_26
Theory : new!event-ordering
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