Nuprl Lemma : eo-record-record

r:eo_record{i:l}(). (r ∈ record(x.eo-record-type{i:l}(r) x))


Proof




Definitions occuring in Statement :  eo-record-type: eo-record-type{i:l}(r) eo_record: eo_record{i:l}() all: x:A. B[x] member: t ∈ T apply: a record: record(x.T[x])
Definitions unfolded in proof :  all: x:A. B[x] eo_record: eo_record{i:l}() record+: record+ member: t ∈ T record-select: r.x subtype_rel: A ⊆B eq_atom: =a y ifthenelse: if then else fi  btrue: tt uall: [x:A]. B[x] guard: {T} prop: eo-record-type: eo-record-type{i:l}(r) record: record(x.T[x]) implies:  Q bool: 𝔹 unit: Unit it: uiff: uiff(P;Q) and: P ∧ Q uimplies: supposing a squash: T label: ...$L... t sq_type: SQType(T) true: True iff: ⇐⇒ Q rev_implies:  Q bfalse: ff exists: x:A. B[x] or: P ∨ Q bnot: ¬bb assert: b false: False top: Top

Latex:
\mforall{}r:eo\_record\{i:l\}().  (r  \mmember{}  record(x.eo-record-type\{i:l\}(r)  x))



Date html generated: 2016_05_16-AM-09_13_22
Last ObjectModification: 2016_01_17-PM-01_32_35

Theory : new!event-ordering


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