Nuprl Lemma : fpf-cap-join-subtype
∀[A:Type]. ∀[eq:EqDecider(A)]. ∀[f,g:a:A fp-> Type]. ∀[a:A]. (f ⊕ g(a)?Top ⊆r f(a)?Top)
Proof
Definitions occuring in Statement :
fpf-join: f ⊕ g,
fpf-cap: f(x)?z,
fpf: a:A fp-> B[a],
deq: EqDecider(T),
subtype_rel: A ⊆r B,
uall: ∀[x:A]. B[x],
top: Top,
universe: Type
Lemmas :
fpf_wf,
deq_wf,
fpf-join-cap,
subtype-fpf2,
top_wf,
subtype_top,
fpf-dom_wf,
bool_wf,
eqtt_to_assert,
subtype_rel_self,
fpf-ap_wf,
eqff_to_assert,
equal_wf,
bool_cases_sqequal,
subtype_base_sq,
bool_subtype_base,
assert-bnot
\mforall{}[A:Type]. \mforall{}[eq:EqDecider(A)]. \mforall{}[f,g:a:A fp-> Type]. \mforall{}[a:A]. (f \moplus{} g(a)?Top \msubseteq{}r f(a)?Top)
Date html generated:
2015_07_17-AM-11_13_44
Last ObjectModification:
2015_01_28-AM-07_42_29
Home
Index