Nuprl Lemma : lnk-decl-dom-single
∀[l:IdLnk]. ∀[k:Knd]. ∀[tg:Id]. ∀[v:Top]. (k ∈ dom(lnk-decl(l;tg : v)) ~ rcv(l,tg) = k)
Proof
Definitions occuring in Statement :
lnk-decl: lnk-decl(l;dt),
fpf-single: x : v,
fpf-dom: x ∈ dom(f),
eq_knd: a = b,
Kind-deq: KindDeq,
rcv: rcv(l,tg),
Knd: Knd,
IdLnk: IdLnk,
Id: Id,
uall: ∀[x:A]. B[x],
top: Top,
sqequal: s ~ t
Lemmas :
map_cons_lemma,
map_nil_lemma,
deq_member_cons_lemma,
deq_member_nil_lemma,
eq_knd_wf,
rcv_wf,
bool_wf,
eqtt_to_assert,
eqff_to_assert,
equal_wf,
bool_cases_sqequal,
subtype_base_sq,
bool_subtype_base,
assert-bnot,
top_wf,
Id_wf,
Knd_wf,
IdLnk_wf
\mforall{}[l:IdLnk]. \mforall{}[k:Knd]. \mforall{}[tg:Id]. \mforall{}[v:Top]. (k \mmember{} dom(lnk-decl(l;tg : v)) \msim{} rcv(l,tg) = k)
Date html generated:
2015_07_17-AM-11_15_33
Last ObjectModification:
2015_01_28-AM-07_38_27
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