Nuprl Lemma : qreal-function

[f:ℝ ⟶ ℝ ⟶ ℝ]. f ∈ [ℝ] ⟶ [ℝ] ⟶ [ℝsupposing ∀a1,a2,b1,b2:ℝ.  ((a1 a2)  (b1 b2)  (f[a1;b1] f[a2;b2]))


Proof




Definitions occuring in Statement :  qreal: [ℝ] req: y real: uimplies: supposing a uall: [x:A]. B[x] so_apply: x[s1;s2] all: x:A. B[x] implies:  Q member: t ∈ T function: x:A ⟶ B[x]
Definitions unfolded in proof :  uall: [x:A]. B[x] member: t ∈ T uimplies: supposing a qreal: [ℝ] quotient: x,y:A//B[x; y] and: P ∧ Q so_lambda: λ2y.t[x; y] so_apply: x[s1;s2] all: x:A. B[x] implies:  Q prop: so_lambda: λ2x.t[x] so_apply: x[s]
Lemmas referenced :  qreal_wf quotient-member-eq real_wf req_wf req-equiv equal-wf-base all_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity isect_memberFormation introduction cut functionExtensionality sqequalHypSubstitution pointwiseFunctionalityForEquality functionEquality lemma_by_obid hypothesis sqequalRule pertypeElimination productElimination thin because_Cache isectElimination lambdaEquality hypothesisEquality independent_isectElimination dependent_functionElimination applyEquality independent_functionElimination equalityTransitivity equalitySymmetry productEquality axiomEquality isect_memberEquality

Latex:
\mforall{}[f:\mBbbR{}  {}\mrightarrow{}  \mBbbR{}  {}\mrightarrow{}  \mBbbR{}]
    f  \mmember{}  [\mBbbR{}]  {}\mrightarrow{}  [\mBbbR{}]  {}\mrightarrow{}  [\mBbbR{}]  supposing  \mforall{}a1,a2,b1,b2:\mBbbR{}.    ((a1  =  a2)  {}\mRightarrow{}  (b1  =  b2)  {}\mRightarrow{}  (f[a1;b1]  =  f[a2;b2]))



Date html generated: 2016_05_18-AM-11_14_42
Last ObjectModification: 2015_12_27-PM-10_39_41

Theory : reals


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