Step
*
1
of Lemma
sine0
1. Σi.-1^i * (r0^(2 * i) + 1)/((2 * i) + 1)! = sine(r0)
⊢ sine(r0) = r0
BY
{ Assert ⌜Σi.-1^i * (r0^(2 * i) + 1)/((2 * i) + 1)! = r0⌝⋅ }
1
.....assertion.....
1. Σi.-1^i * (r0^(2 * i) + 1)/((2 * i) + 1)! = sine(r0)
⊢ Σi.-1^i * (r0^(2 * i) + 1)/((2 * i) + 1)! = r0
2
1. Σi.-1^i * (r0^(2 * i) + 1)/((2 * i) + 1)! = sine(r0)
2. Σi.-1^i * (r0^(2 * i) + 1)/((2 * i) + 1)! = r0
⊢ sine(r0) = r0
Latex:
Latex:
1. \mSigma{}i.-1\^{}i * (r0\^{}(2 * i) + 1)/((2 * i) + 1)! = sine(r0)
\mvdash{} sine(r0) = r0
By
Latex:
Assert \mkleeneopen{}\mSigma{}i.-1\^{}i * (r0\^{}(2 * i) + 1)/((2 * i) + 1)! = r0\mkleeneclose{}\mcdot{}
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