Nuprl Lemma : derivative-rexp-fun2

f,f':ℝ ⟶ ℝ.
  ((∀x,y:ℝ.  ((x y)  (f'[x] f'[y])))
   d(f[x])/dx = λx.f'[x] on (-∞, ∞)
   d(e^f[x])/dx = λx.e^f[x] f'[x] on (-∞, ∞))


Proof




Definitions occuring in Statement :  derivative: d(f[x])/dx = λz.g[z] on I riiint: (-∞, ∞) rexp: e^x req: y rmul: b real: so_apply: x[s] all: x:A. B[x] implies:  Q function: x:A ⟶ B[x]
Definitions unfolded in proof :  all: x:A. B[x] implies:  Q member: t ∈ T subtype_rel: A ⊆B rfun: I ⟶ℝ top: Top uall: [x:A]. B[x] so_lambda: λ2x.t[x] so_apply: x[s] prop: uimplies: supposing a label: ...$L... t guard: {T}
Lemmas referenced :  derivative-rexp-fun riiint_wf member_riiint_lemma subtype_rel_dep_function real_wf true_wf subtype_rel_self set_wf iproper-riiint req_wf i-member_wf derivative_wf all_wf
Rules used in proof :  sqequalSubstitution sqequalTransitivity computationStep sqequalReflexivity lambdaFormation cut introduction extract_by_obid sqequalHypSubstitution dependent_functionElimination thin hypothesis hypothesisEquality applyEquality sqequalRule isect_memberEquality voidElimination voidEquality isectElimination lambdaEquality setEquality independent_isectElimination setElimination rename because_Cache independent_functionElimination functionExtensionality functionEquality

Latex:
\mforall{}f,f':\mBbbR{}  {}\mrightarrow{}  \mBbbR{}.
    ((\mforall{}x,y:\mBbbR{}.    ((x  =  y)  {}\mRightarrow{}  (f'[x]  =  f'[y])))
    {}\mRightarrow{}  d(f[x])/dx  =  \mlambda{}x.f'[x]  on  (-\minfty{},  \minfty{})
    {}\mRightarrow{}  d(e\^{}f[x])/dx  =  \mlambda{}x.e\^{}f[x]  *  f'[x]  on  (-\minfty{},  \minfty{}))



Date html generated: 2017_10_04-PM-10_18_01
Last ObjectModification: 2017_06_24-PM-00_05_50

Theory : reals_2


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