Nuprl Lemma : strong-continuity2-no-inner-squash-unique

F:(ℕ ⟶ ℕ) ⟶ ℕ
  ⇃(∃M:n:ℕ ⟶ (ℕn ⟶ ℕ) ⟶ (ℕ?)
     ∀f:ℕ ⟶ ℕ. ∃n:ℕ(((M f) (inl (F f)) ∈ (ℕ?)) ∧ (∀m:ℕ((↑isl(M f))  (m n ∈ ℕ)))))


Proof




Definitions occuring in Statement :  quotient: x,y:A//B[x; y] int_seg: {i..j-} nat: assert: b isl: isl(x) all: x:A. B[x] exists: x:A. B[x] implies:  Q and: P ∧ Q true: True unit: Unit apply: a function: x:A ⟶ B[x] inl: inl x union: left right natural_number: $n equal: t ∈ T
Definitions unfolded in proof :  squash: T cand: c∧ B and: P ∧ Q uimplies: supposing a member: t ∈ T uall: [x:A]. B[x] all: x:A. B[x] strong-continuity3: strong-continuity3(T;F)
Lemmas referenced :  subtype_rel_self nat_wf strong-continuity3-half-squash
Rules used in proof :  functionEquality dependent_functionElimination baseClosed hypothesisEquality imageMemberEquality independent_functionElimination independent_pairFormation because_Cache independent_isectElimination hypothesis thin isectElimination sqequalHypSubstitution extract_by_obid introduction cut lambdaFormation computationStep sqequalTransitivity sqequalReflexivity sqequalRule sqequalSubstitution

Latex:
\mforall{}F:(\mBbbN{}  {}\mrightarrow{}  \mBbbN{})  {}\mrightarrow{}  \mBbbN{}
    \00D9(\mexists{}M:n:\mBbbN{}  {}\mrightarrow{}  (\mBbbN{}n  {}\mrightarrow{}  \mBbbN{})  {}\mrightarrow{}  (\mBbbN{}?)
          \mforall{}f:\mBbbN{}  {}\mrightarrow{}  \mBbbN{}.  \mexists{}n:\mBbbN{}.  (((M  n  f)  =  (inl  (F  f)))  \mwedge{}  (\mforall{}m:\mBbbN{}.  ((\muparrow{}isl(M  m  f))  {}\mRightarrow{}  (m  =  n)))))



Date html generated: 2017_09_29-PM-06_05_38
Last ObjectModification: 2017_09_03-PM-09_28_17

Theory : continuity


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