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Step * of Lemma strong-subtype-deq-subtype

∀[A,B:Type].  EqDecider(B) ⊆r EqDecider(A) supposing strong-subtype(A;B)
BY
{ (Auto THEN D 0 THEN Auto THEN BLemma `strong-subtype-deq` THEN Auto) }

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Latex:

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Latex:
\mforall{}[A,B:Type].    EqDecider(B)  \msubseteq{}r  EqDecider(A)  supposing  strong-subtype(A;B)


By

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Latex:
(Auto  THEN  D  0  THEN  Auto  THEN  BLemma  `strong-subtype-deq`  THEN  Auto)

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