Nuprl Lemma : has-value-append-nil
∀[l:Base]. (l)↓ supposing (l @ [])↓
Proof
Definitions occuring in Statement :
append: as @ bs,
nil: [],
has-value: (a)↓,
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
base: Base
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
uimplies: b supposing a,
append: as @ bs,
list_ind: list_ind,
has-value: (a)↓,
prop: ℙ
Lemmas referenced :
base_wf,
has-value_wf_base
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
sqequalHypSubstitution,
sqequalRule,
callbyvalueCallbyvalue,
hypothesis,
callbyvalueReduce,
axiomSqleEquality,
lemma_by_obid,
isectElimination,
thin,
baseApply,
closedConclusion,
baseClosed,
hypothesisEquality,
isect_memberEquality,
because_Cache,
equalityTransitivity,
equalitySymmetry
Latex:
\mforall{}[l:Base]. (l)\mdownarrow{} supposing (l @ [])\mdownarrow{}
Date html generated:
2016_05_14-AM-06_31_20
Last ObjectModification:
2016_01_14-PM-08_24_45
Theory : list_0
Home
Index