Step
*
1
1
4
1
of Lemma
isOdd-sum
1. n : ℤ
2. 0 < n
3. f : ℕn ⟶ ℤ
4. Σ(f[x] | x < n) = (Σ(f[x] | x < n - 1) + f[n - 1]) ∈ ℤ
5. v : ℤ
6. Σ(f[x] | x < n - 1) = v ∈ ℤ
7. v1 : ℤ
8. ¬↑same-parity(v;v1)
9. f[n - 1] = v1 ∈ ℤ
10. v2 : ℕ
11. ||filter(λx.isOdd(f[x]);upto(n - 1))|| = v2 ∈ ℕ
12. ↑isOdd(v)
13. ↑isEven(v1)
14. ¬False
15. ↑isOdd(v2)
16. ↑isOdd(v)
17. ↑isOdd(v1)
⊢ ¬↑same-parity(v2;1)
BY
{ (RWO "even-iff-not-odd" (-5) THEN Auto) }
Latex:
Latex:
1. n : \mBbbZ{}
2. 0 < n
3. f : \mBbbN{}n {}\mrightarrow{} \mBbbZ{}
4. \mSigma{}(f[x] | x < n) = (\mSigma{}(f[x] | x < n - 1) + f[n - 1])
5. v : \mBbbZ{}
6. \mSigma{}(f[x] | x < n - 1) = v
7. v1 : \mBbbZ{}
8. \mneg{}\muparrow{}same-parity(v;v1)
9. f[n - 1] = v1
10. v2 : \mBbbN{}
11. ||filter(\mlambda{}x.isOdd(f[x]);upto(n - 1))|| = v2
12. \muparrow{}isOdd(v)
13. \muparrow{}isEven(v1)
14. \mneg{}False
15. \muparrow{}isOdd(v2)
16. \muparrow{}isOdd(v)
17. \muparrow{}isOdd(v1)
\mvdash{} \mneg{}\muparrow{}same-parity(v2;1)
By
Latex:
(RWO "even-iff-not-odd" (-5) THEN Auto)
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