Step
*
1
2
of Lemma
lcm-assoc-nat
1. n : ℕ
2. m : ℕ
3. k : ℕ
4. lcm(n;m) | lcm(n;lcm(m;k))
⊢ k | lcm(n;lcm(m;k))
BY
{ (UseTrans ⌜lcm(m;k)⌝⋅ THEN Auto THEN BLemma `lcm-is-lcm-nat` ⋅ THEN Auto) }
Latex:
Latex:
1. n : \mBbbN{}
2. m : \mBbbN{}
3. k : \mBbbN{}
4. lcm(n;m) | lcm(n;lcm(m;k))
\mvdash{} k | lcm(n;lcm(m;k))
By
Latex:
(UseTrans \mkleeneopen{}lcm(m;k)\mkleeneclose{}\mcdot{} THEN Auto THEN BLemma `lcm-is-lcm-nat` \mcdot{} THEN Auto)
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