Step
*
1
1
1
1
of Lemma
twosquareinv-fixpoint
1. p : {p:{2...}| prime(p)}
2. x : ℕ
3. y : ℕ
4. z : ℕ
5. ¬x < y - z
6. ((x * x) + (4 * y * z)) = p ∈ ℤ
7. ¬(x = 0 ∈ ℤ)
8. ¬(z = 0 ∈ ℤ)
9. x < y + y
10. ((y + y) - x) = x ∈ ℕ
11. y = y ∈ ℕ
12. ((x - y) + z) = z ∈ ℕ
13. x = y ∈ ℤ
14. p = (1 * (1 + (4 * z))) ∈ ℤ
15. y = 1 ∈ ℤ
⊢ <1, 1, z> = <1, 1, (p - 1) ÷ 4> ∈ (x:ℕ × y:ℕ × {z:ℕ| ((x * x) + (4 * y * z)) = p ∈ ℤ} )
BY
{ RepeatFor 2 (EqCDA) }
1
.....subterm..... T:t
2:n
1. p : {p:{2...}| prime(p)}
2. x : ℕ
3. y : ℕ
4. z : ℕ
5. ¬x < y - z
6. ((x * x) + (4 * y * z)) = p ∈ ℤ
7. ¬(x = 0 ∈ ℤ)
8. ¬(z = 0 ∈ ℤ)
9. x < y + y
10. ((y + y) - x) = x ∈ ℕ
11. y = y ∈ ℕ
12. ((x - y) + z) = z ∈ ℕ
13. x = y ∈ ℤ
14. p = (1 * (1 + (4 * z))) ∈ ℤ
15. y = 1 ∈ ℤ
⊢ z = ((p - 1) ÷ 4) ∈ {z:ℕ| ((1 * 1) + (4 * 1 * z)) = p ∈ ℤ}
Latex:
Latex:
1. p : \{p:\{2...\}| prime(p)\}
2. x : \mBbbN{}
3. y : \mBbbN{}
4. z : \mBbbN{}
5. \mneg{}x < y - z
6. ((x * x) + (4 * y * z)) = p
7. \mneg{}(x = 0)
8. \mneg{}(z = 0)
9. x < y + y
10. ((y + y) - x) = x
11. y = y
12. ((x - y) + z) = z
13. x = y
14. p = (1 * (1 + (4 * z)))
15. y = 1
\mvdash{} ə, 1, z> = ə, 1, (p - 1) \mdiv{} 4>
By
Latex:
RepeatFor 2 (EqCDA)
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