Nuprl Lemma : false-sqequal

∀[a,b:Base].  ((¬(a ~ b)) ⇒ ((a ~ b) = (0 ~ 1) ∈ Type))


Proof




Definitions occuring in Statement :  uall: ∀[x:A]. B[x],  not: ¬A,  implies: P ⇒ Q,  natural_number: $n,  base: Base,  universe: Type,  sqequal: s ~ t,  equal: s = t ∈ T
Definitions unfolded in proof :  uall: ∀[x:A]. B[x],  member: t ∈ T,  implies: P ⇒ Q,  iff: P ⇐⇒ Q,  and: P ∧ Q,  not: ¬A,  false: False,  rev_implies: P ⇐ Q,  uimplies: b supposing a,  sq_type: SQType(T),  all: ∀x:A. B[x],  guard: {T},  squash: ↓T,  prop: ℙ,  true: True
Lemmas referenced :  subtype_base_sq,  base_wf,  subtype_rel_self,  false_wf,  int_subtype_base
Rules used in proof :  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  Error :isect_memberFormation_alt,  introduction,  cut,  Error :lambdaFormation_alt,  sqequalExtensionalEquality,  independent_pairFormation,  sqequalHypSubstitution,  independent_functionElimination,  thin,  hypothesis,  voidElimination,  Error :universeIsType,  because_Cache,  instantiate,  extract_by_obid,  isectElimination,  cumulativity,  independent_isectElimination,  dependent_functionElimination,  hypothesisEquality,  sqequalIntensionalEquality,  baseClosed,  sqequalRule,  imageMemberEquality,  Error :functionIsType,  Error :lambdaEquality_alt,  axiomEquality,  Error :functionIsTypeImplies,  Error :inhabitedIsType,  Error :isect_memberEquality_alt,  Error :isectIsTypeImplies,  equalitySymmetry,  equalityTransitivity,  intEquality,  natural_numberEquality

Latex:
\mforall{}[a,b:Base].    ((\mneg{}(a  \msim{}  b))  {}\mRightarrow{}  ((a  \msim{}  b)  =  (0  \msim{}  1)))



Date html generated: 2019_06_20-AM-11_19_43
Last ObjectModification: 2018_10_15-PM-10_52_07

Theory : sqequal_1


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