Nuprl Lemma : inl-one-one

∀[A,B:Type]. ∀[x,y:A].  uiff((inl x) = (inl y) ∈ (A + B);x = y ∈ A)


Proof




Definitions occuring in Statement :  uiff: uiff(P;Q),  uall: ∀[x:A]. B[x],  inl: inl x,  union: left + right,  universe: Type,  equal: s = t ∈ T
Definitions unfolded in proof :  prop: ℙ,  uimplies: b supposing a,  and: P ∧ Q,  uiff: uiff(P;Q),  member: t ∈ T,  uall: ∀[x:A]. B[x]
Lemmas referenced :  equal_wf
Rules used in proof :  universeEquality,  equalitySymmetry,  equalityTransitivity,  axiomEquality,  isect_memberEquality,  independent_pairEquality,  productElimination,  because_Cache,  inlEquality,  cumulativity,  unionEquality,  isectElimination,  extract_by_obid,  hypothesis,  hypothesisEquality,  thin,  unionElimination,  applyLambdaEquality,  sqequalRule,  sqequalHypSubstitution,  independent_pairFormation,  cut,  introduction,  isect_memberFormation,  sqequalReflexivity,  computationStep,  sqequalTransitivity,  sqequalSubstitution

Latex:
\mforall{}[A,B:Type].  \mforall{}[x,y:A].    uiff((inl  x)  =  (inl  y);x  =  y)



Date html generated: 2018_05_21-PM-00_00_52
Last ObjectModification: 2017_12_11-PM-06_47_06

Theory : union


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