Step * 1 2 of Lemma bag-subtract-no-repeats


1. Type
2. eq EqDecider(T)
3. T
4. List
5. ∀bs:bag(T). (bag-no-repeats(T;bs)  bag-no-repeats(T;bag-subtract(eq;bs;v)))
6. bs bag(T)
7. bag-no-repeats(T;bs)
⊢ bag-no-repeats(T;bag-subtract(eq;bs;[u v]))
BY
(RepUR ``bag-subtract bag-accum`` THEN Fold `bag-accum` THEN Fold `bag-subtract` THEN BackThruSomeHyp) }

1
1. Type
2. eq EqDecider(T)
3. T
4. List
5. ∀bs:bag(T). (bag-no-repeats(T;bs)  bag-no-repeats(T;bag-subtract(eq;bs;v)))
6. bs bag(T)
7. bag-no-repeats(T;bs)
⊢ bag-no-repeats(T;bag-drop(eq;bs;u))


Latex:


Latex:

1.  T  :  Type
2.  eq  :  EqDecider(T)
3.  u  :  T
4.  v  :  T  List
5.  \mforall{}bs:bag(T).  (bag-no-repeats(T;bs)  {}\mRightarrow{}  bag-no-repeats(T;bag-subtract(eq;bs;v)))
6.  bs  :  bag(T)
7.  bag-no-repeats(T;bs)
\mvdash{}  bag-no-repeats(T;bag-subtract(eq;bs;[u  /  v]))


By


Latex:
(RepUR  ``bag-subtract  bag-accum``  0
  THEN  Fold  `bag-accum`  0
  THEN  Fold  `bag-subtract`  0
  THEN  BackThruSomeHyp)




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