Step
*
1
1
1
of Lemma
sbdecode-code
1. m : ℕ
2. ∀m:ℕm. ∀[n:ℕ]. (0 < m
⇒ 0 < n
⇒ (sbdecode(sbcode(m;n)) ~ <m ÷ gcd(m;n), n ÷ gcd(m;n)>))
3. n : ℕ
4. ∀n:ℕn. (0 < m
⇒ 0 < n
⇒ (sbdecode(sbcode(m;n)) ~ <m ÷ gcd(m;n), n ÷ gcd(m;n)>))
5. 0 < m
6. 0 < n
7. m < n
8. 0 < gcd(m;n)
⊢ gcd(n - m;m) = gcd(n;m) ∈ ℤ
BY
{ xxx(RWO "gcd_subtract" 0 THEN Auto)xxx }
Latex:
Latex:
1. m : \mBbbN{}
2. \mforall{}m:\mBbbN{}m. \mforall{}[n:\mBbbN{}]. (0 < m {}\mRightarrow{} 0 < n {}\mRightarrow{} (sbdecode(sbcode(m;n)) \msim{} <m \mdiv{} gcd(m;n), n \mdiv{} gcd(m;n)>))
3. n : \mBbbN{}
4. \mforall{}n:\mBbbN{}n. (0 < m {}\mRightarrow{} 0 < n {}\mRightarrow{} (sbdecode(sbcode(m;n)) \msim{} <m \mdiv{} gcd(m;n), n \mdiv{} gcd(m;n)>))
5. 0 < m
6. 0 < n
7. m < n
8. 0 < gcd(m;n)
\mvdash{} gcd(n - m;m) = gcd(n;m)
By
Latex:
xxx(RWO "gcd\_subtract" 0 THEN Auto)xxx
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