Nuprl Lemma : null-strict
∀[a:Base]. (a)↓ supposing (null(a))↓
Proof
Definitions occuring in Statement :
null: null(as),
has-value: (a)↓,
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
base: Base
Definitions unfolded in proof :
uall: ∀[x:A]. B[x],
member: t ∈ T,
uimplies: b supposing a,
null: null(as),
has-value: (a)↓,
prop: ℙ
Lemmas referenced :
base_wf,
has-value_wf_base
Rules used in proof :
sqequalSubstitution,
sqequalTransitivity,
computationStep,
sqequalReflexivity,
isect_memberFormation,
introduction,
cut,
sqequalHypSubstitution,
callbyvalueIspair,
hypothesis,
sqequalRule,
axiomSqleEquality,
lemma_by_obid,
isectElimination,
thin,
baseApply,
closedConclusion,
baseClosed,
hypothesisEquality,
isect_memberEquality,
because_Cache,
equalityTransitivity,
equalitySymmetry
Latex:
\mforall{}[a:Base]. (a)\mdownarrow{} supposing (null(a))\mdownarrow{}
Date html generated:
2016_05_15-PM-02_07_18
Last ObjectModification:
2016_01_15-PM-10_24_01
Theory : untyped!computation
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