 Q == P+Q
 Q == P+Qis mentioned by
|  Q   Q | [or_fused] | 
|  Q     P   Q | [disjunct_elim] | 
|  P:Prop.   P   P)   (  P:Prop. P    P) | [negnegelim_vs_bivalence] | 
|  Q &  (P & Q) | [xor] | 
In prior sections: core bool 1 rel 1
Try larger context:
 
DiscrMathExt
IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html