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At: propositional decidability 1

1. S: Sequent

|= S (a:Assignment. a | S)

By:
Inst Thm* G:Sequent. L:Sequent List. sL.((s) = 0) & (sL.|= s |= G ) & (a:Assignment. sL.a | s a | G) [S]
THEN
Repeat (Analyze -1)


Generated subgoal:

12. L: Sequent List
3. sL.((s) = 0)
4. sL.|= s |= S
5. a:Assignment. sL.a | s a | S
|= S (a:Assignment. a | S)


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