f:(A
A), k:
, i:{0...k}. f{
k} = f{i} o f{k-i}x:A, f:(AA), k:, i:{0...k}. f{k}(x) = f{i}(f{k-i}(x))| Rank | Theorem | Name |
| 3 | f:(AA), k:, i:{0...k}. f{k} = f{i} o f{k-i} | [compose_iter_sum_comp_rw] |
| cites the following: | ||
| 2 | x:A, f:(AA), k:, i:{0...k}. f{k}(x) = f{i}(f{k-i}(x)) | [compose_iter_sum_rw] |