x:A, f:(A
A), k:
, i:{0...k}. f{
k}(x) = f{i}(f{k-i}(x))x:A, f:(AA), i,j,k:. k = i+j 
f{i}(f{j}(x)) = f{k}(x)| Rank | Theorem | Name |
| 2 | x:A, f:(AA), k:, i:{0...k}. f{k}(x) = f{i}(f{k-i}(x)) | [compose_iter_sum_rw] |
| cites the following: | ||
| 1 | x:A, f:(AA), i,j,k:. k = i+j f{i}(f{j}(x)) = f{k}(x) | [compose_iter_sum] |