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Def Surj(A; B; f) == b:B. a:A. f(a) = b
is mentioned by
Def Bij(A; B; f) == Inj(A; B; f) & Surj(A; B; f) | [biject] |
Try larger context:
StandardLIB
IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html