graph 1 1 Sections Graphs Doc

Def Bij(A; B; f) == Inj(A; B; f) & Surj(A; B; f)

is mentioned by

Thm* f:(AB). Bij(A; B; f) (g:(BA). Bij(B; A; g) & InvFuns(A; B; f; g))[inverse-biject]
Thm* f:(AB), g:(BC). Bij(A; B; f) Bij(B; C; g) Bij(A; C; g o f)[compose-biject]
Thm* Bij(T; T; Id)[identity-biject]

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graph 1 1 Sections Graphs Doc