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Bij(A; B; f) == Inj(A; B; f) & Surj(A; B; f)
is mentioned by
Thm*
f:(A
B). Bij(A; B; f)
(
g:(B
A). Bij(B; A; g) & InvFuns(A; B; f; g))
[inverse-biject]
Thm*
f:(A
B), g:(B
C). Bij(A; B; f)
Bij(B; C; g)
Bij(A; C; g o f)
[compose-biject]
Thm*
Bij(T; T; Id)
[identity-biject]
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