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At: choose functionality axiom

  T:S, P,Q:(TType). (x:TP(x Q(x))  (@x:TP(x)) = (@x:TQ(x))

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1   T:S, P,Q:(TType). (x:TP(x Q(x))  (@x:TP(x)) = (@x:TQ(x))
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functionuniverseequalimpliesall
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