Nuprl - Proof: iter via intseg null

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html
Iteration over a null sequence is the identity element.

A:Type, f:(A

A), u:A, a,b:

, e:({a..b

}

A).

(Iter(f;u) i:{a..b

}. e(i)) = u

By:

Auto

Generated subgoal:

1 1. A : Type
2. f : AAA
3. u : A
4. a :
5. b :
6. e : {a..b}A
7. ba
(Iter(f;u) i:{a..b}. e(i)) = u
1 step

About:

IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html