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Def
as @ bs == Case of as; nil
bs ; a.as'
[a / (as' @ bs)] (recursive)
is mentioned by
Thm*
d:Decl, t1,t2:(
d) List, P:(Label
). t1 @ t2 | P ~ (t1 | P @ t2 | P)
[trace_projection_append]
In prior sections:
list
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