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At: fun exp add1 1

1. T : Type
2. f : TT
3. n : 
4. T
  f^n+1 = f o f^n


By: Inst Thm* n,m:f:(TT). f^n+m = f^n o f^m [T;1;n;f]


Generated subgoal:

1 5. f^1+n = f^1 o f^n
  f^n+1 = f o f^n

2 steps

About:
natural_numberaddfunctionuniverseequalall
IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html

(4steps total) PrintForm Definitions Lemmas mb nat Sections MarkB generic Doc