Nuprl - Proof: iteration terminates 1

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At: iteration terminates 1

1. T : Type
2. f : T

T
3. m : T

4.

x:T. m(f(x))

m(x) & (m(f(x)) = m(x)

f(x) = x)
5. x : T

n:

. f(f^n(x)) = f^n(x)

By:	Assert (n:. m(f^n(x))m(x)-n f(f^n(x)) = f^n(x))

Generated subgoals:

1   n:. m(f^n(x))m(x)-n  f(f^n(x)) = f^n(x)
14 steps

2 6. n:. m(f^n(x))m(x)-n  f(f^n(x)) = f^n(x)
  n:. f(f^n(x)) = f^n(x)
12 steps

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IF YOU CAN SEE THIS go to /sfa/Nuprl/Shared/Xindentation_hack_doc.html

(28steps total) PrintForm Definitions Lemmas mb nat Sections MarkB generic Doc