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At: sum difference 1 1

1. n : 
2. f : n
3. g : n
4. d : 
5. sum(f(x)-g(x) | x < n) = d
  sum(f(x) | x < n) = sum(g(x)+f(x)-g(x) | x < n)


By: BackThru
Thm* n:f,g:(n).
Thm* (i:nf(i) = g(i))  sum(f(x) | x < n) = sum(g(x) | x < n)


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About:
intnatural_numberaddsubtractfunctionequalimpliesall
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(3steps total) PrintForm Definitions Lemmas mb nat Sections MarkB generic Doc