1 |
4. f : n 
5. m: (n-1+1). sum(f(x) | x < n-1) = sum(f(x) | x < m)+sum(f(x+m) | x < n-1-m)
6. m : (n+1)
7. m = n-1
sum(f(x) | x < n) = sum(f(x) | x < m)+sum(f(x+m) | x < n-m)
 | 4 steps |
2 |
4. f : n 
5. m: (n-1+1). sum(f(x) | x < n-1) = sum(f(x) | x < m)+sum(f(x+m) | x < n-1-m)
6. m : (n+1)
7. m = n-1
sum(f(x) | x < n) = sum(f(x) | x < m)+sum(f(x+m) | x < n-m)
 | 5 steps |