S:Sequent. (S) < ( < hyp,concl > ) (L:Sequent List. sL.((s) = 0) & (sL.|= s |= S ) & (a:Assignment. sL.a | s a | S))

fhyp.((f) > 0)

fconcl.((f) > 0)

( < hyp,concl > ) = 0

s[ < hyp,concl > ].((s) = 0) & (s[ < hyp,concl > ].|= s |= < hyp,concl > ) & (a:Assignment. s[ < hyp,concl > ].a | s a | < hyp,concl > )

1	6. (hyp)+(concl) = 0 7. a: Assignment 8. a | < hyp,concl > False a | < hyp,concl >

About: