Nuprl Lemma : rank-comm
∀[P:pi_term()]. ∀[pre:pi_prefix()]. (pi-rank(picomm(pre;P)) = (pi-rank(P) + 1) ∈ ℕ)
Proof
Definitions occuring in Statement :
pi-rank: pi-rank(p),
picomm: picomm(pre;body),
pi_term: pi_term(),
pi_prefix: pi_prefix(),
nat: ℕ,
uall: ∀[x:A]. B[x],
add: n + m,
natural_number: $n,
equal: s = t ∈ T
Lemmas :
zero-le-nat,
pi-rank_wf,
picomm_wf,
nat_wf,
le_wf,
pi_prefix_wf,
pi_term_wf
Latex:
\mforall{}[P:pi\_term()]. \mforall{}[pre:pi\_prefix()]. (pi-rank(picomm(pre;P)) = (pi-rank(P) + 1))
Date html generated:
2015_07_23-AM-11_33_08
Last ObjectModification:
2015_01_29-AM-00_54_12
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