Nuprl Lemma : ma-ring-all-in-remove-repeats-steps2

R:Id List. s:{i:Id| (i  R)}   {i:Id| (i  R)} . x:{i:Id| (i  R)} .
  (ma-ring(R;s)  (y:{i:Id| (i  R)} . n:||remove-repeats(IdDeq;R)||. (y = (s^n x))))


Proof not projected




Definitions occuring in Statement :  ma-ring: ma-ring(R;s) id-deq: IdDeq Id: Id length: ||as|| int_seg: {i..j} all: x:A. B[x] exists: x:A. B[x] implies: P  Q set: {x:A| B[x]}  apply: f a function: x:A  B[x] list: type List natural_number: $n equal: s = t l_member: (x  l) fun_exp: f^n remove-repeats: remove-repeats(eq;L)
Lemmas :  ma-ring-all-in-remove-repeats-steps1 Id_wf l_member_wf ma-ring_wf

\mforall{}R:Id  List.  \mforall{}s:\{i:Id|  (i  \mmember{}  R)\}    {}\mrightarrow{}  \{i:Id|  (i  \mmember{}  R)\}  .  \mforall{}x:\{i:Id|  (i  \mmember{}  R)\}  .
    (ma-ring(R;s)  {}\mRightarrow{}  (\mforall{}y:\{i:Id|  (i  \mmember{}  R)\}  .  \mexists{}n:\mBbbN{}||remove-repeats(IdDeq;R)||.  (y  =  (s\^{}n  x))))


Date html generated: 2012_02_20-PM-05_56_01
Last ObjectModification: 2012_02_02-PM-02_29_50

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