{ 
[A:Type]. [B:A 
Type]. [eq:EqDecider(A)]. [f,g,h:a:A fp-> B[a]].
(f 
h) supposing (g h and f g) }
{ Proof }
Definitions occuring in Statement :
fpf-sub: f g,
fpf: a:A fp-> B[a],
uimplies: b supposing a,
uall: [x:A]. B[x],
so_apply: x[s],
function: x:A B[x],
universe: Type,
deq: EqDecider(T)
Definitions :
uall: [x:A]. B[x],
so_apply: x[s],
uimplies: b supposing a,
fpf-sub: f g,
member: t 
T,
all: x:A. B[x],
implies: P 
Q,
cand: A c
B,
prop: 
,
so_lambda: 
x.t[x],
and: P Q
Lemmas :
assert_wf,
fpf-dom_wf,
fpf-trivial-subtype-top,
pair_wf,
assert_witness,
fpf-sub_wf,
fpf_wf,
deq_wf,
assert_elim,
bool_wf
\mforall{}[A:Type]. \mforall{}[B:A {}\mrightarrow{} Type]. \mforall{}[eq:EqDecider(A)]. \mforall{}[f,g,h:a:A fp-> B[a]].
(f \msubseteq{} h) supposing (g \msubseteq{} h and f \msubseteq{} g)
Date html generated:
2011_08_10-AM-07_57_20
Last ObjectModification:
2011_06_18-AM-08_17_38
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