{ 
[Info,A,B:Type]. [f:A 
B]. [X:EClass(A)].
((f[v] where v from X) 
EClass(B)) }
{ Proof }
Definitions occuring in Statement :
map-class: (f[v] where v from X),
eclass: EClass(A[eo; e]),
uall: [x:A]. B[x],
so_apply: x[s],
member: t T,
function: x:A B[x],
universe: Type
Definitions :
single-bag: {x},
es-filter-image: f[X],
subtype: S 
T,
event_ordering: EO,
es-E: E,
event-ordering+: EO+(Info),
lambda: 
x.A[x],
all: x:A. B[x],
axiom: Ax,
apply: f a,
so_apply: x[s],
map-class: (f[v] where v from X),
universe: Type,
function: x:A B[x],
uall: [x:A]. B[x],
so_lambda: 
x y.t[x; y],
isect: 
x:A. B[x],
member: t T,
equal: s = t,
eclass: EClass(A[eo; e])
Lemmas :
eclass_wf,
es-E_wf,
event-ordering+_inc,
event-ordering+_wf,
es-filter-image_wf,
single-bag_wf
\mforall{}[Info,A,B:Type]. \mforall{}[f:A {}\mrightarrow{} B]. \mforall{}[X:EClass(A)]. ((f[v] where v from X) \mmember{} EClass(B))
Date html generated:
2011_08_16-PM-04_14_56
Last ObjectModification:
2011_06_20-AM-00_44_22
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