Nuprl Lemma : hdf-base-ap

[A,B:Type]. ∀[F:A ─→ bag(B)]. ∀[a:A].  (hdf-base(m.F[m])(a) = <hdf-base(m.F[m]), F[a]> ∈ (hdataflow(A;B) × bag(B)))


Proof




Definitions occuring in Statement :  hdf-base: hdf-base(m.F[m]) hdf-ap: X(a) hdataflow: hdataflow(A;B) uall: [x:A]. B[x] so_apply: x[s] function: x:A ─→ B[x] pair: <a, b> product: x:A × B[x] universe: Type equal: t ∈ T bag: bag(T)
Lemmas :  hdf-ap-run hdf-base_wf bag_wf
\mforall{}[A,B:Type].  \mforall{}[F:A  {}\mrightarrow{}  bag(B)].  \mforall{}[a:A].    (hdf-base(m.F[m])(a)  =  <hdf-base(m.F[m]),  F[a]>)



Date html generated: 2015_07_17-AM-08_05_16
Last ObjectModification: 2015_01_27-PM-00_15_58

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