Step
*
1
of Lemma
better-r2-straightedge-compass
.....assertion.....
1. c : ℝ^2
2. d : ℝ^2
3. a : ℝ^2
4. b : {b:ℝ^2| b ≠ a ∧ c_b_d}
⊢ ∃q:ℝ^2. (q_a_b ∧ (d(c;d) < d(c;q)))
BY
{ Assert ⌜∀x:ℝ. ∃q:ℝ^2. (b-a-q ∧ (x < d(b;q)))⌝⋅ }
1
.....assertion.....
1. c : ℝ^2
2. d : ℝ^2
3. a : ℝ^2
4. b : {b:ℝ^2| b ≠ a ∧ c_b_d}
⊢ ∀x:ℝ. ∃q:ℝ^2. (b-a-q ∧ (x < d(b;q)))
2
1. c : ℝ^2
2. d : ℝ^2
3. a : ℝ^2
4. b : {b:ℝ^2| b ≠ a ∧ c_b_d}
5. ∀x:ℝ. ∃q:ℝ^2. (b-a-q ∧ (x < d(b;q)))
⊢ ∃q:ℝ^2. (q_a_b ∧ (d(c;d) < d(c;q)))
Latex:
Latex:
.....assertion.....
1. c : \mBbbR{}\^{}2
2. d : \mBbbR{}\^{}2
3. a : \mBbbR{}\^{}2
4. b : \{b:\mBbbR{}\^{}2| b \mneq{} a \mwedge{} c\_b\_d\}
\mvdash{} \mexists{}q:\mBbbR{}\^{}2. (q\_a\_b \mwedge{} (d(c;d) < d(c;q)))
By
Latex:
Assert \mkleeneopen{}\mforall{}x:\mBbbR{}. \mexists{}q:\mBbbR{}\^{}2. (b-a-q \mwedge{} (x < d(b;q)))\mkleeneclose{}\mcdot{}
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