Nuprl Lemma : evalall-sqequal2
∀[x:Base]. evalall(x) ~ x supposing (evalall(x))↓
Proof
Definitions occuring in Statement :
has-value: (a)↓,
evalall: evalall(t),
uimplies: b supposing a,
uall: ∀[x:A]. B[x],
base: Base,
sqequal: s ~ t
Lemmas referenced :
evalall-sqequal
Rules used in proof :
cut,
lemma_by_obid,
hypothesis
Latex:
\mforall{}[x:Base]. evalall(x) \msim{} x supposing (evalall(x))\mdownarrow{}
Date html generated:
2016_05_13-PM-04_07_37
Last ObjectModification:
2015_12_26-AM-11_03_53
Theory : fun_1
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