Step
*
of Lemma
has-valueall-cons
∀[a,b:Base]. uiff(has-valueall(a) ∧ has-valueall(b);has-valueall([a / b]))
BY
{ (Unfold `has-valueall` 0
THEN Auto
THEN Try ((RecUnfold `evalall` 0
THEN Reduce 0
THEN RepeatFor 2 ((CallByValueReduce 0 THEN Auto))
THEN Reduce 0
THEN Auto))
THEN (RecUnfold `evalall` (-1) THEN Reduce (-1) THEN RepeatFor 2 ((HasValueD (-1) THEN Auto THEN Thin (-1))))⋅) }
Latex:
Latex:
\mforall{}[a,b:Base]. uiff(has-valueall(a) \mwedge{} has-valueall(b);has-valueall([a / b]))
By
Latex:
(Unfold `has-valueall` 0
THEN Auto
THEN Try ((RecUnfold `evalall` 0
THEN Reduce 0
THEN RepeatFor 2 ((CallByValueReduce 0 THEN Auto))
THEN Reduce 0
THEN Auto))
THEN (RecUnfold `evalall` (-1)
THEN Reduce (-1)
THEN RepeatFor 2 ((HasValueD (-1) THEN Auto THEN Thin (-1))))\mcdot{})
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