Nuprl Lemma : equiv_rel-wf-per-quotient

[T:Type]. ∀[E1,E2:T ⟶ T ⟶ 𝔹].
  (EquivRel(T;x,y.↑E2[x;y])
   EquivRel(T;x,y.↑E1[x;y])
   (∀x,y:T.  ((↑E2[x;y])  (↑E1[x;y])))
   (E1 ∈ (x,y:T/per/(↑E2[x;y])) ⟶ (x,y:T/per/(↑E2[x;y])) ⟶ 𝔹))


Proof




Definitions occuring in Statement :  per-quotient: x,y:T/per/E[x; y] equiv_rel: EquivRel(T;x,y.E[x; y]) assert: b bool: 𝔹 uall: [x:A]. B[x] so_apply: x[s1;s2] all: x:A. B[x] implies:  Q member: t ∈ T function: x:A ⟶ B[x] universe: Type
Definitions unfolded in proof :  per-quotient: x,y:T/per/E[x; y] quotient: x,y:A//B[x; y]
Lemmas referenced :  equiv_rel-wf-quotient
Rules used in proof :  cut introduction extract_by_obid sqequalRule sqequalReflexivity sqequalSubstitution sqequalTransitivity computationStep hypothesis

Latex:
\mforall{}[T:Type].  \mforall{}[E1,E2:T  {}\mrightarrow{}  T  {}\mrightarrow{}  \mBbbB{}].
    (EquivRel(T;x,y.\muparrow{}E2[x;y])
    {}\mRightarrow{}  EquivRel(T;x,y.\muparrow{}E1[x;y])
    {}\mRightarrow{}  (\mforall{}x,y:T.    ((\muparrow{}E2[x;y])  {}\mRightarrow{}  (\muparrow{}E1[x;y])))
    {}\mRightarrow{}  (E1  \mmember{}  (x,y:T/per/(\muparrow{}E2[x;y]))  {}\mrightarrow{}  (x,y:T/per/(\muparrow{}E2[x;y]))  {}\mrightarrow{}  \mBbbB{}))



Date html generated: 2019_06_20-PM-00_33_40
Last ObjectModification: 2018_08_21-PM-10_50_34

Theory : per-quotient


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