Step
*
of Lemma
equal-p-adics
∀[p:ℕ+]. ∀[x,y:p-adics(p)]. uiff(x = y ∈ p-adics(p);x = y ∈ (ℕ+ ⟶ ℤ))
BY
{ (Intro
THEN (Assert p-adics(p) ⊆r (ℕ+ ⟶ ℤ) BY
Auto)
THEN Intros
THEN (RepeatFor 2 (D 0) THENA Auto)
THEN DVar `x'
THEN DVar `y'
THEN ((EqTypeHD (-1) THEN Auto) ORELSE (EqTypeCD THEN Auto))) }
Latex:
Latex:
\mforall{}[p:\mBbbN{}\msupplus{}]. \mforall{}[x,y:p-adics(p)]. uiff(x = y;x = y)
By
Latex:
(Intro
THEN (Assert p-adics(p) \msubseteq{}r (\mBbbN{}\msupplus{} {}\mrightarrow{} \mBbbZ{}) BY
Auto)
THEN Intros
THEN (RepeatFor 2 (D 0) THENA Auto)
THEN DVar `x'
THEN DVar `y'
THEN ((EqTypeHD (-1) THEN Auto) ORELSE (EqTypeCD THEN Auto)))
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