Step * of Lemma pa-sep_wf

[p:{2...}]. ∀[x,y:basic-padic(p)].  (pa-sep(p;x;y) ∈ ℙ)
BY
ProveWfLemma }


Latex:


Latex:
\mforall{}[p:\{2...\}].  \mforall{}[x,y:basic-padic(p)].    (pa-sep(p;x;y)  \mmember{}  \mBbbP{})


By


Latex:
ProveWfLemma




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