Nuprl Lemma : bdd-diff_functionality

∀x1,x2,y1,y2:ℕ+ ⟶ ℤ.  (bdd-diff(x1;x2) ⇒ bdd-diff(y1;y2) ⇒ (bdd-diff(x1;y1) ⇐⇒ bdd-diff(x2;y2)))


Proof




Definitions occuring in Statement :  bdd-diff: bdd-diff(f;g),  nat_plus: ℕ+,  all: ∀x:A. B[x],  iff: P ⇐⇒ Q,  implies: P ⇒ Q,  function: x:A ⟶ B[x],  int: ℤ
Definitions unfolded in proof :  all: ∀x:A. B[x],  implies: P ⇒ Q,  iff: P ⇐⇒ Q,  and: P ∧ Q,  equiv_rel: EquivRel(T;x,y.E[x; y]),  member: t ∈ T,  prop: ℙ,  uall: ∀[x:A]. B[x],  rev_implies: P ⇐ Q,  trans: Trans(T;x,y.E[x; y]),  guard: {T},  sym: Sym(T;x,y.E[x; y])
Lemmas referenced :  bdd-diff-equiv,  bdd-diff_wf,  nat_plus_wf
Rules used in proof :  sqequalSubstitution,  sqequalTransitivity,  computationStep,  sqequalReflexivity,  lambdaFormation,  independent_pairFormation,  cut,  lemma_by_obid,  sqequalHypSubstitution,  productElimination,  thin,  isectElimination,  hypothesisEquality,  hypothesis,  functionEquality,  intEquality,  dependent_functionElimination,  independent_functionElimination

Latex:
\mforall{}x1,x2,y1,y2:\mBbbN{}\msupplus{}  {}\mrightarrow{}  \mBbbZ{}.    (bdd-diff(x1;x2)  {}\mRightarrow{}  bdd-diff(y1;y2)  {}\mRightarrow{}  (bdd-diff(x1;y1)  \mLeftarrow{}{}\mRightarrow{}  bdd-diff(x2;y2)))



Date html generated: 2016_05_18-AM-06_46_32
Last ObjectModification: 2015_12_28-AM-00_24_51

Theory : reals


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